A long solenoid with 15 turns per cm has a small loop of area 2 cubic cm placed inside the solenoid to its axis. If the current carried by the solenoid changes steadily from 2 Ampere to 4 Ampere in 0.1 second. What is the induced emf in the loop while the current is changing.
Physics
Class 12
1895
Aanya
Number of turns on the solenoid = 15 turns/cm = 1500 turns/m (convert per cm to per m by dividing 100)
Number of turns per unit length, n = 1500 turns
The Solenoid has a small loop of area, A = 2 cm3 = 2 x 10 -4 m2
Also, Current carried by the solenoid changes from 2 A to 4 A. Therefore change in current in the solenoid is given by Faraday's Las is given by the formula is
e = dφ/dt ........ (1)
where φ = Induced flux through the small loop = BA . . . (2)
Hence, equation 1 becomes
e = d/dt (BA)
= A μ0 n x (di/dt)
= 2 x 10-4 x 4π x 10-7 x 1500 x 2/0.1
= 7.54 x 10-6 V
Hence, the induced voltage in the loop is 7.54 x 10-6 V