Mathematics
Class 8
1102
Chakrika
First, we factorisation, 68600 i.e. 68600 = 2 × 2 × 2 × 5 × 5 × 7 × 7 × 7.
In this factorization, we find that there is a triplet of 2 and 7 but no triplet of 5. Therefore, 68600 is not a perfect cube.
To make 68600 a perfect cube we multiply it by 5.
Thus, 68600 × 5 = 2 × 2 × 2 × 5 × 5 × 5 × 7 × 7 × 7 = 343000, which is a perfect cube.